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OpenStudy (anonymous):
Given that cos θ = frac{1}{9}, calculate the value of sin θ.
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OpenStudy (anonymous):
I am really stuck on this problem.
OpenStudy (anonymous):
so to solve sin, first you have to solve for cos
OpenStudy (anonymous):
there are 2 ways to do this, pythagorean or using calculators to find degrees.
OpenStudy (anonymous):
I'll show you both, choose one you like more?
OpenStudy (anonymous):
both
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OpenStudy (solomonzelman):
1² + b² = 9²
sin = b / 9
OpenStudy (amistre64):
sin^2 + cos^2 = 1 :)
OpenStudy (anonymous):
cos theta= 1/9
cos^-1 (1/9) = theta
theta = 83.62 degrees
sin 83.62= 0.9938
OpenStudy (anonymous):
and the second was solomon's way :D
OpenStudy (anonymous):
why do you square -1?
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OpenStudy (anonymous):
a^2 + b^2 = c^2
pythagorean theorem
OpenStudy (anonymous):
so you do pythagorean theorem then sin
OpenStudy (anonymous):
on 2nd though pythagorean would not be applicable for every problems since we don't know if this is a right triangle or not.
OpenStudy (anonymous):
thought*
just use your calc to find cos and sin instead.
or you can use sin^2 + cos^2 = 1 , that one is always true
OpenStudy (anonymous):
ok thanks
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