Given that cos θ = frac{1}{9}, calculate the value of sin θ.
I am really stuck on this problem.
so to solve sin, first you have to solve for cos
there are 2 ways to do this, pythagorean or using calculators to find degrees.
I'll show you both, choose one you like more?
both
1² + b² = 9² sin = b / 9
sin^2 + cos^2 = 1 :)
cos theta= 1/9 cos^-1 (1/9) = theta theta = 83.62 degrees sin 83.62= 0.9938
and the second was solomon's way :D
why do you square -1?
a^2 + b^2 = c^2 pythagorean theorem
so you do pythagorean theorem then sin
on 2nd though pythagorean would not be applicable for every problems since we don't know if this is a right triangle or not.
thought* just use your calc to find cos and sin instead. or you can use sin^2 + cos^2 = 1 , that one is always true
ok thanks
Join our real-time social learning platform and learn together with your friends!