Question

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Answer 1

ARea of the square= 8 -12x + 9 = 17 -12x

Since the area of square = a * a

Which is equal to:

\[Area = 17 - 12x\]

We know that:

\[Area = (side)^2\]

therefore length/side/a(whatever you call it):

\[=\sqrt{17-12x}\]

Answer 2

@NoCopsForMiles

Answer 3

But if you meant(I guess) this:

\[4x^2-12x+9\]

Then factorising it equals to:

\[=4x^2-6x-6x+9 = 2x(2x -3) -3(2x -3)\]

=\[(2x-3)(2x-3)\]

Therfore according to the formula of the area of the square:

\[A = (side)\]

side/length/a(whatever you call it):

= (2x-3)