What is the solution to the equation 1/ the square root of 8=4^(m-3)

Question

solomonzelman · Answer

$\LARGE\color{blue}{     \frac{1}{\sqrt{8}}=4^{(m-3)}  }$  like this ?

anonymous · Answer

$$\frac{ 1 }{ \sqrt{8}}= 4^{(m-3)}$$

anonymous · Answer

yes

solomonzelman · Answer

$\LARGE\color{blue}{     \frac{1}{\sqrt{8}}=4^{(m-3)}  }$

$\LARGE\color{blue}{     \frac{1}{\sqrt{8}}=(2^2)^{(m-3)}  }$

$\LARGE\color{blue}{     \frac{1}{\sqrt{8}}=2^{2(m-3)}  }$

$\LARGE\color{blue}{     \sqrt{8}^{~~-1}=2^{2(m-3)}  }$

$\LARGE\color{blue}{     \sqrt{2^3}^{~~-1}=2^{2(m-3)}  }$

$\LARGE\color{blue}{     \sqrt[2]{2^3}^{~~-1}=2^{2(m-3)}  }$

$\LARGE\color{blue}{     (2^{3/2})^{~~-1}=2^{2(m-3)}  }$

$\LARGE\color{blue}{     2^{~~-1(3/2)}=2^{2(m-3)}  }$

solomonzelman · Answer

then you get    -1(3/2) = 2(m-3)

solomonzelman · Answer

-3/2 = 2m - 6 
6 -3/2 = 2m  
12/2 -3/2 = 2m  
9/2 = 2m  
9/4 = m

solomonzelman · Answer

Let me know if you need more help.

anonymous · Answer

ohhh ok I understand it better now thank you.

solomonzelman · Answer

Anytime :)