The distance traveled, in feet, of a ball dropped from a tall building is modeled by the equation d(t) = 16t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 2 to t = 5 represent?

Question

anonymous · Answer

Answer Choices: 

 The ball travels an average distance of 112 feet from 2 seconds to 5 seconds.

 The ball falls down with an average speed of 48 feet per second from 2 seconds to 5 seconds.

 The ball falls down with an average speed of 112 feet per second from 2 seconds to 5 seconds.

 The ball travels an average distance of 48 feet from 2 seconds to 5 seconds.

anonymous · Answer

the old fashion slope

d(t1)-d(t0)
---------------
t1-t0


where t0 is initial time and t1 is final time.

anonymous · Answer

plug in the numbers. I am pretty suure that is what it is.

anonymous · Answer

Plug in the numbers to what?

anonymous · Answer

lets just say t1 is final time so therefore it is 5  

and thust d(t1)=d(5)   = 16(5)2    do same for d(t0)  

need more help?

anonymous · Answer

Oh okay

anonymous · Answer

so then it would be 16(2)2 ?

anonymous · Answer

Im thinking it would be A?

anonymous · Answer

it is basical m= slope 
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