The number of fish (f) in a fish tank increases when the number of algae blooms (a) decreases. Write the correct equation for this scenario, and solve for the number of fish when there are 4 algae blooms. algae blooms fish 10 10 25 4 a) f = 1a; f = 4 b) f = .1a; f = .4 c) f = 100 over a; f = 25 d) f = 100 over a; f = 400
Your best bet is to substitute what you have into the chart to see if it works correctly with the equations.
well it seems like inverse variation \[f = \frac{k}{a}\] so substitute f 10 and a = 10 then solve for k. the variation constant. when you find k, substitute b = 4 to find the number of fish
oops substitute a = 4 to find the number of fish
@campbell_st yeah i was like WAIT WHERE DID THE B COME FROM haha
so it would be A
well what valeu did you get for k...?
4
C seems to be the most reasonable one tbh. Cause 10 = 100/10 is correct and 4 = 100/25 is also correct
im stupid
no... look at the equation again \[10 = \frac{k}{10}\] solve for k
...100?
dude 1
its 1 isnt it
thats correct so the equation you will use is \[fish = \frac{100}{a}\] now substitute a = 4 to find the number of fish
is a still 10 or is that gone now ?
no 4
25
no... you need to confirm the number of fish increases as the blooms decrease... to the other information you have been given is that the fish = 25 when the blooms = 4 so using the equation \[f = \frac{100}{a}\] substitute a = 4 and confirm f = 25
but how is that confirmed ?
if you confirm its correct.... then find the equation in your answer choices and the fact that f = 25
By solving the equation with a being 4
ah so it is C ! like dariel said
substitution is the process of replacing a letter by a number so using a = 4 and substituting into \[f = \frac{100}{a}\] you will be able to calculate f \[f = \frac{100}{4}\] so what is f... if you do the calculation above...?
Both our methods works, just mine is not always as reliable :3
both fantastic helpers thanks ! ^.^
no problem
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