Question

Please help i am really stuck ! Find three consecutive integers such that the sum of the first and twice the third is one more than three times the second.
Thanks for all help!!! :)

Answer 1

what are consecutive integers? :3

Answer 2

let the 3 integers be n , n+1 and n+2

then we have

n + 2(n + 2) = 3(n + 1) + 1

solve for n

Answer 3

but this is an identity !!???

Answer 4

so there are infinite solution

Answer 5

are you sure you have the question right/

Answer 6

yea idk maybe it was a misprint

Answer 7

as it stands you can fit any number to n 1,2,3.....

Answer 8

- or negative ones for that matter

Answer 9

n = 1st integer
n + 1 = 2nd integer
n + 2 = 3rd integer

n + 2(n + 2) = 3(n + 1) + 1
n + 2n + 4 = 3n + 3 + 1
3n + 4 = 3n + 4

I agree...infinite solutions