Question

Vertex form to standard
f(x) = (x - 4)^2 -4

Answer 1

Just expand (x-4)^2
do you know how to do this?

Answer 2

it becomes (x-2)(x-2)

Answer 3

no! it is (x-4)(x-4)
then FOIL

Answer 4

thats where I mess up.

Answer 5

\(\Large \tt\color{blueviolet}{(x-4)(x-4)=x^2-4x-4x+16=x^2-8x+16}\)

Answer 6

thank you so muchh!!

Answer 7

yw!
you are not finished yet you know

Answer 8

so what happened to the -4?

Answer 9

u add +4??

Answer 10

no you subtract 4 from what we got above

Answer 11

\(\Large \tt\color{blueviolet}{f(x)=x^2-8x+16-4}\)

Answer 12

now complete the it to the final answer

Answer 13

f(x)=x^2-8x+12

Answer 14

Correct!

Answer 15

thank youu

Answer 16

Anytime!

Answer 17

hmm

Answer 18

@nincompoop hehe

Answer 19

f(x) = a(x-h)^2 + k
try to convert
f(x) = 2(x+2)^2 - 1 into standard-form just to make sure you learned what you were taught

Answer 20

\(\Large \tt\color{blueviolet}{He~is~gone}\)
not sure he got this lol