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Mathematics
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Solving Quadratic Equations
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\[\frac{ \sqrt{18} }{3\sqrt{2}}\]
well rewrite \[\sqrt{18}= \sqrt{9 \times 2} = \sqrt{9} \times \sqrt{2} = 3\sqrt{2}\]
K...so after doing that what do I do? Because you can't have a square root in the denominator.
well look at it this way \[\frac{\sqrt{18}}{3\sqrt{2}} = \frac{3\sqrt{2}}{3\sqrt{2}}\] what do you think it simplifies to..?
3 root 4 ver 3?
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no.... its simply 1
\(\bf \cfrac{\sqrt{18}}{3\sqrt{2}} = \cfrac{\cancel{ 3\sqrt{2} }}{\cancel{ 3\sqrt{2} }}\)
\(\bf \cfrac{\cancel{ same }}{\cancel{ same }}=1\)
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