Write an equation in slope intercept form of the line that passes through (4, 1) and (5, -1). y = -4x + 1 y = -1/2 x + 9 y = 4x + 1 y = -2x + 9
first we need to find the slope \[slope=\frac{ y2-y1 }{ x2-x1}\] \[\frac{ -1-1 }{ 5-4 }\]
-2/1 slope
can that be simplified?
no
yes it can :) anything whats -2 divided by 1?
you can make a small 2 by x, and by y, say `y_2` or `x_2`
-2
now lets put it in \[y-y_1=m(x-x_1)\] using the coordinates (4,1) and because the slope is -2 our m is -2
-1-1 = -2 (5-4)
leave the first x and y alone \[y-1=-2(x-4)\]
can you distribute our slope?
yes
alright do that please dont forget 2 negatives will make a positive
(-2*x) - (-2*4) -2-(-8) -10
you almost had it right only you would leave -2 alone and add the x and make -8 a positive \[y-1=-2x+8\]
now to isolate y we have to get -1 on the other side how would we do that?
add -1 to both sides?
y = -2x + 9?
yes you got it :)
Write an equation of the line that passes through (8, 3) and (4, 3). would this be y=3?
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