A line passes through (–9, –5) and (2, –4). a. Write an equation for the line in point-slope form. b. Rewrite the equation in standard form using integers.
alright you are going to start out by finding the slope of the line using this equation \[m= (y2-y1)\div (x2-x1)\]
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ -9}}\quad ,&{\color{blue}{ -5}})\quad &({\color{red}{ 2}}\quad ,&{\color{blue}{ -4}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}} \\ \quad \\ y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values }\\ \qquad \uparrow\\ \textit{point-slope form}\)
standard form, means flush all variables to the left-side and leave the constant on the right-side
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