Question

C=4d^-1/3b, Solve for d

Answer 1

Try to isolate d

Answer 2

multiply 3b to both sides

Answer 3

So you'll have 3bc=4d^-1
You'd have to put d as a denominator under 4 (4 being the numerator)

Like this:3bc=4/d
Then you can multiply 4 to both sides
12bc=d

Answer 4

\(\bf a^{-{\color{red} n}} = \cfrac{1}{a^{\color{red} n}}\qquad thus
\\ \quad \\ \quad \\

c=\cfrac{4d^{-1}}{3b}\implies c=\cfrac{4}{3b}\cdot d^{-1}\implies c=\cfrac{4}{3b}\cdot \cfrac{1}{d^1}
\\ \quad \\
c=\cfrac{4}{3bd}\)

solve for "d"