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simplify the expression and solve the equation
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\[\frac{ 2h^2-2h-4 }{ (h+1)(h-2) }+\frac{ h^2+h-2 }{ (h+2)(h-1) }\]
Alright give meh a second
Remove the extra parentheses. 2h2−2h−4/(h+1)(h−2) + h2+h−2/(h+2)(h−1)=h Factor the numerator. 2(h−2)(h+1)/(h+1)(h−2) + h2+h−2/(h+2)(h−1)=h Reduce the expression by canceling out all common factors from the numerator and denominator. 2+h2+h−2(h+2)(h−1)=h Factor the numerator. 2 + (h+2)(h−1)/(h+2)(h−1)=h Reduce the expression by canceling out all common factors from the numerator and denominator. 2+1=h Add 1 to 2 to get 3. 3=h Since h is on the right-hand side of the equation, switch the sides so it is on the left-hand side of the equation. h=3
@aballer101
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