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OpenStudy (anonymous):
Describe and correct the error
k + 5 = -2k
k+5 k+3 k2 +8k+15
LCD= (k+3)(k+5)
k(k+3)+5(k+5)=-2k
k2 +3k+5k+25=-2k
k2 +8k+25=-2k
k2 +10k+25=0
(k+5)2 =0
k=-5
OpenStudy (anonymous):
@Broskishelleh
OpenStudy (broskishelleh):
I don't see the original equation
OpenStudy (anonymous):
Thats the equation and there is an error in it that I have to describe and correct
OpenStudy (broskishelleh):
Well k = -5/3
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OpenStudy (anonymous):
so everything else is right except that?
OpenStudy (broskishelleh):
nah i need to find the mistake
OpenStudy (anonymous):
okay
OpenStudy (broskishelleh):
@aballer101 Can I list the steps?
OpenStudy (anonymous):
sure
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OpenStudy (broskishelleh):
Since −2k contains the variable to solve for, move it to the left-hand side of the equation by adding 2k to both sides.
k+5+2k=0
Since k and 2k are like terms, add 2k to k to get 3k.
3k+5=0
Since 5 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 5 from both sides.
3k=−5
Divide each term in the equation by 3.
k=−5/3