Ask your own question, for FREE!
Mathematics 20 Online
OpenStudy (anonymous):

For each of these three equations, determine whether there are any solution(s). If there are solutions, say what they are and show how you found them. If there aren't solutions, explain why not. (a) x/3+x/4+ x/5 =2x/3 + 2x/4 + 2x/5 (b) y/3+y/4+ y/5 = y/3+ y/4+ y/5+1 (c) z/3+ z/4+ z/5 =z/4+z/5+ z/6+1

OpenStudy (tkhunny):

Didn't we just do this? You have some arithmetic in front of you. Have at it. A little work in Common Denominators, I'd say.

OpenStudy (tkhunny):

Can you add x/3 + x/4?

OpenStudy (tkhunny):

Of course, you don't actually need to do that. Just checking. (a) Factor out 2 from the right hand side. Anything look cool? (b) Subtract the three variable-laden terms. What's left? (c) Two of the variable terms match up. Subtract them is see if you can tell where to go.

OpenStudy (tkhunny):

Note: If you don't like a response, ASK. Don't just close and start all over. Note: Please read the Code of Conduct and heed its wisdom. Posting a problem with no discussion and no work shown is not okay. Give us a clue where you are.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!