Find the slope of the line that passes through these points: (-6,-1), (-6,4)
@aum @campbell_st @ganeshie8
@beccaboo333
\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &({\color{red}{ -6}}\quad ,&{\color{blue}{ -1}})\quad &({\color{red}{ -6}}\quad ,&{\color{blue}{ 4}}) \end{array} \\\quad \\ slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}\)
Won't there be a zero in the denominator?
yes, that means the slope is "undefined" and when the slope is "undefined" that means that the "run" values are equally the same across the whole line that means a vertical line so for any "y" value, "x" is always -6 thus |dw:1408491946337:dw|
Ohh ok thanks
yw
bye
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