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Geometry 5 Online
OpenStudy (anonymous):

Find the distance of x.

OpenStudy (anonymous):

OpenStudy (anonymous):

|dw:1408516774073:dw| Hopefully this helps you figure out how to solve this.

OpenStudy (anonymous):

oh awkward I set up my problem completely different I did the Pythagorean theorem. like I put x^2 +130^2=(130+145)^2

OpenStudy (anonymous):

It will be a Pythagorean problem. The equation you need to solve is \[(65+29)^2 + (65+29)^2 = (2x)^2\]

OpenStudy (anonymous):

okay so I got 841 + 841 = 4x so 841+841 = 1747 and divide that by the 4x and I get 436.75

OpenStudy (anonymous):

Remember, it isn't 4x, but 4x^2

OpenStudy (anonymous):

oh so the square root of that would be 20.898

OpenStudy (anonymous):

Sorry, just looking over your math. I think your numbers are a little off. Your squares are off. It should be \[94^2 + 94 ^2 = 4x^2\] \[8836 + 8836 = 4x^2\] \[17672 = 4x^2\] \[4418 = x^2\] \[x = 66.47\]

OpenStudy (anonymous):

x=29*130

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