Question

what is the point of discontinuity for y=x^2-x-12/-x^2-2x+3

Answer 1

x = 0 might be.

Of course, if you actually mean y=(x^2-x-12)/(-x^2-2x+3), there will be a different answer.

Please remember your Order of Operations. Include necessary parentheses.

Answer 2

\(\large {
y=\cfrac{x^2-x-12}{{\color{brown}{ -x^2-2x+3}}}\quad if\quad {\color{brown}{ -x^2-2x+3}}=0\quad
\\ \quad \\
then\quad y=\cfrac{x^2-x-12}{{\color{brown}{ 0}}}\leftarrow
\begin{cases}
undefined\\
discontinous
\end{cases}
}\)

so see what values of "x" make the denominator 0