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Mathematics 20 Online
OpenStudy (anonymous):

Which set of line segments with the given lengths can be formed into a right triangle? 24, 30, 35 12, 18, 30 18, 24, 30 18,24, 35

OpenStudy (anonymous):

a common right side triangle has a side of 3, a side of 4 and a side of 5 units of length. If any of those options can divide in such a way that one side an be divided by 3, another by 4 and yet another by 5 than that's the one.

OpenStudy (anonymous):

Oh, I didn't know that. Thanks

OpenStudy (anonymous):

|dw:1408636614725:dw|

OpenStudy (anonymous):

that's because 3^2 + 4^2 = 5^2 (9+16=25)

OpenStudy (anonymous):

Okee dokee

OpenStudy (anonymous):

I will keep that on mind from now on, cause i did not know that until now, lol.

OpenStudy (anonymous):

they must also result in the same number when you divide off course otherwise the scale is off

OpenStudy (anonymous):

okay, thanks very much!

OpenStudy (triciaal):

note that 3, 4, 5 is not the only option for a right triangle what about 5, 12, 13?

OpenStudy (triciaal):

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OpenStudy (triciaal):

for a triangle with lengths a,b,c if it is a right triangle the hypotenuse, c is always the longest side and opposite the right angle and the sum of the square of the legs = square of the hypotenuse a^2 + b^2 = c^2

OpenStudy (triciaal):

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