Evaluating an integral by pieces...
Where am I wrong? @cwrw238 @Agentjamesbond007 @agent0smith @Compassionate @jdoe0001 @lului @Luigi0210 @nubeer
why did you type in cosd theta rather than cos theta?
Good question. My bad.
But do I need to do the substituion again or is that the only issue?
I assume you did u = 9\(\theta\) du = 9 dθ dv = cosθ dθ v= sinθ and did \[ \int u\ dv = uv - \int v \ du \]
Yes. Matches perfectly.
so except for the extra d, your solution looks good
Yay! The computer took it! I have one more question. If the last part would have been multiplied by something rather than a constant (9), like another sin theta, would I have had to do the substation twice?
if you multiply by a function of theta, then it is definitely more complicated. In fact, we may have to use a different trick than integration by parts... it depends
Ok. I was just wondering. My prof. said some of the problems I would have to substitute twice and one I would have to use algebra.
when you get to that problem you probably will notice. If you need, help you can post it.
Ok. Thanks Phi!!!!!!!!!!!!!
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