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Mathematics 13 Online
OpenStudy (anonymous):

What is the approximate surface area of this pencil? (Use 3 point one four for pi. Round your answer to the nearest whole number.) twenty-eight square centimeters 41 cm2 30 cm2 seventy square centimeters

OpenStudy (anonymous):

OpenStudy (math&ing001):

That would be the surface of the cylinder (minus one base) + the surface area of the cone.(without the base).

OpenStudy (math&ing001):

@V1r3z

OpenStudy (aum):

Surface area of hemisphere on the left + lateral surface area of cylinder + lateral surface area of cone. Rounded to the nearest whole number or to the nearest answer.

OpenStudy (math&ing001):

There is no semisphere on the left @aum that's just how the cylinder is drawn.

OpenStudy (aum):

Could be just a flat circular base of a cylinder or a hemispherical eraser at the end of a pencil Since the radius is small it may not make much difference if it is pi*r^2 or 2*pi*r^2.

OpenStudy (aum):

Assuming the left end is just a flat circular surface, the total surface area = \(\large \pi r^2 + 2\pi rL + \pi r l = \pi r( r + 2L + l)\) where r is the radius of the pencil; L is the length of the cylinder; and l is the slant height of the cone. Plug in the numbers and calculate the total surface area.

OpenStudy (math&ing001):

If you look close enough you'll see there's no sphere. Plus if there were they would've drawn it clearly like the others. And if you do the math you'll 30 cm², no place for an additional surface.

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