What is the approximate surface area of this pencil? (Use 3 point one four for pi. Round your answer to the nearest whole number.) twenty-eight square centimeters 41 cm2 30 cm2 seventy square centimeters
That would be the surface of the cylinder (minus one base) + the surface area of the cone.(without the base).
@V1r3z
Surface area of hemisphere on the left + lateral surface area of cylinder + lateral surface area of cone. Rounded to the nearest whole number or to the nearest answer.
There is no semisphere on the left @aum that's just how the cylinder is drawn.
Could be just a flat circular base of a cylinder or a hemispherical eraser at the end of a pencil Since the radius is small it may not make much difference if it is pi*r^2 or 2*pi*r^2.
Assuming the left end is just a flat circular surface, the total surface area = \(\large \pi r^2 + 2\pi rL + \pi r l = \pi r( r + 2L + l)\) where r is the radius of the pencil; L is the length of the cylinder; and l is the slant height of the cone. Plug in the numbers and calculate the total surface area.
If you look close enough you'll see there's no sphere. Plus if there were they would've drawn it clearly like the others. And if you do the math you'll 30 cm², no place for an additional surface.
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