Question

Match each equation with the description of the first step you can take to solve the equation.

Match Term Definition
k−sixths minus eight−fifteenths equals negative four−fifteenths A) Subtract four−fifteenths from both sides.
negative four−fifteenths plus k−sixths equals negative eight−fifteenths B) Subtract eight−fifteenths from both sides.
k−sixths plus four−fifteenths equals negative eight−fifteenths C) Add eight−fifteenths to both sides.
eight−fifteenths plus k−sixths equals negative four−fifteenths D) Add four−fifteenths to both sides.

Answer 1

k/6 -8/15=-415
A good first step is to combine like terms while getting the constant term on the opposite side of the equals sign from the x term.. Do you know how to do that?

Answer 2

no @JoannaBlackwelder

Answer 3

Add 8/15 to both sides :) That gets the -8/15 on the right to combine with the -4/15 and away from the x term.

Answer 4

Make sense?

Answer 5

@izzyoct05 ?

Answer 6

yes thank you. is that the first questions answer?

Answer 7

@JoannaBlackwelder

Answer 8

Yes :)

Answer 9

Can you try the next one?

Answer 10

yes :)

Answer 11

:)

Answer 12

would i add 4/15 to both sides?

Answer 13

Perfect! :)

Answer 14

And the next one?

Answer 15

I gotta go soon, but I'll be back on later on. :)

Answer 16

Happy studies and good job so far!

Answer 17

for the next one would you subract 4/15 from both sides?

Answer 18

@JoannaBlackwelder

Answer 19

Yup!

Answer 20

i got the other ones. thank you! can you help me with some more if i need any help? @joannablackwelder

Answer 21

Sure. Just tag me. :)

Answer 22

i have been working on this one for over an hour and i just need the answer and help.

Subtract six and one-half minus four and seven-tenths. Justify your steps.

Answer 23

@joannablackwelder

Answer 24

Wow, an hour?!

Answer 25

I would first convert from mixed numbers to improper fractions.

Answer 26

Multiply the denominator by the whole number and add to the numerator.

Answer 27

6 1/2 = 13/2

Answer 28

Make sense, @izzyoct05 ?