Question

What are the values of x and y?

Answer 1

Hm, interesting. Is this drawn to scale really poorly? or is the 16 the full side and the 12 part of that side?

Answer 2

must be drawn to scale really poorly but idk cause it doesn't say anything about that

Answer 3

Pythagoras thrice.
\[\LARGE x^2=h^2+256\]
\[\LARGE y^2=h^2+144\]
\[\LARGE 784=x^2+y^2\]
3 equations 3 variables.

Answer 4

here h is the perpendicular height that I'm assuming

Answer 5

If you need more assistance in solving then add the first two equations to get
\[\LARGE 784=2h^2+400 = >2h^2=384 =>h^2=192\]

Answer 6

now solve for x and y

Answer 7

I don't understand. Can you please explain how I'm supposed to solve for x and y?

Answer 8

\[\LARGE y^2=h^2+144 = 192+144=336 =>y = \sqrt{336}\]
\[\LARGE x^2=192+256=448 = >x=\sqrt{448}\]

Answer 9

so then when i solve those y would =18.3303027798 and x would =21.1660104885?

Answer 10

but those aren't one of the answer choices...

Answer 11

the choices are
a) x=2 sqrt 3 and y=4
b) x=8 sqrt 7 and y=4 sqrt 21
c) x=8 sqrt 3 and y=8 sqrt 3
d) x=4 sqrt 21 and y=8 sqrt 7

Answer 12

You should REALLY try to improve your simplification.
\[\LARGE x=\sqrt{448}=\sqrt{2.2.2.2.2.7} = 8 \sqrt{7}\]

Answer 13

ok...thank you