Question

Write the expression in algebraic form. [Hint: Sketch a right triangle.]
csc (arctan (x/√2))

Answer 1

To do questions like these, start with the inside funtion
Let u=arctan(x/sqrt(2))
so
tan(u)=x/sqrt(2)
Draw a right triangle and use this equation
Then find the remaining side

then when use that triangle to find csc(u) you are done.


Please start with the drawing.
Then use Pythagorean thm to find missing side.

Let me know if you have trouble.

Answer 2

I went and set: \[y= \arctan(\frac{ x }{ \sqrt{2}}\]

Answer 3

And take the inverse of both sides, so tan(y) = \[\frac{ x }{ \sqrt{2} }\]

Answer 4

Ok draw a right triangle.

Answer 5

Then use that equation to label the side measurements and angle of the triangle

Answer 6

you get the best people to help you here !

Answer 7

I hope, I did that right?

Answer 8

tan is the ratio that gives you opp/adj

Answer 9

\[\frac{x}{\sqrt{2}}=\frac{opp}{adj}\]

Answer 10

Yeah, I know that much. :)

Answer 11

I would simply let the opp measurement be x
and the adjacent measurement be sqrt(2)

Answer 12

Oh, okay.

Answer 13

Do you see how I got that from the equation you gave?