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Algebra 20 Online
OpenStudy (anonymous):

does this look right>>?

OpenStudy (anonymous):

\[y ^{2}(-y+4)-7y ^{3}\]

OpenStudy (anonymous):

simplifying would equal to 3y^2-7y^3

OpenStudy (anonymous):

@Hero

OpenStudy (anonymous):

I was getting:\[4y^2-8y^3\]

OpenStudy (dangerousjesse):

Mind sharing how you got that answer? @Landon_Buckland

OpenStudy (anonymous):

i thought the y^2 time the -y would be -y^2

OpenStudy (mitu12):

i got 4y^2-8y^3

OpenStudy (xapproachesinfinity):

how did you got 3y^2?

OpenStudy (xapproachesinfinity):

you thought wrong dear jcr^_^

OpenStudy (anonymous):

sure, distrubute over the first part..\[4y^2-y^3-7y^3\]combine like terms..\[4y^2-8y^3\]then you can factor out 4y^2 to get..\[4y^2(1-2y)\]

OpenStudy (dangerousjesse):

He subtracted seven from both sides :)

OpenStudy (anonymous):

poops ight then no not 7 from each side im teaching my self this and kinda openstudy no teacher for algebra 2 i aint that dumb @DangerousJesse

OpenStudy (anonymous):

a******

OpenStudy (anonymous):

@DangerousJesse

OpenStudy (dangerousjesse):

Pardon?

OpenStudy (xapproachesinfinity):

lol^_^ \(\LARGE a^n\times a^m=a^{n+m}\)

OpenStudy (dangerousjesse):

Did you just call me that? Ah, how rude..

OpenStudy (anonymous):

u tried saying i subtracted 7 from both sides, uh one thing theres no = sign

OpenStudy (anonymous):

i dont think id be in algebra 2 if i didnt know something that simple

OpenStudy (dangerousjesse):

That's the only way I could see for you to have gotten that :) My mistake haha

OpenStudy (anonymous):

but thanks for help @Landon_Buckland

OpenStudy (anonymous):

yea ur mistake ahahah (x

OpenStudy (xapproachesinfinity):

it's okay to make mistakes^_^

OpenStudy (anonymous):

I got -8y^3+4y^2

OpenStudy (anonymous):

ay u my mamas bf

OpenStudy (anonymous):

ahah thank you (:

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