for these equations –3x1 – 2x2 + 4x3 = 0 2x1 + x2 – 2x3 = 11 How many solutions does the system have?
for the first EQN.1 I guess 3..since the highest degree of a polynmomial determines the n solutions fora equation(correct me If I'm wrong/little diverted(just a little :confused:..sry)) and the same is true for the EQN2
well using a matrix and reducing it, gives:
1 0 0 22 0 1 -2 -33
so wouldnt x3 be a free variable?
meaning infinetly many solutions
wouldnt it just e one free variable?
yes when you have more variables compared to equations, there will always be infinitely many solutions if the solutions exist
Oh yes you're right, one free variable !
1 0 0 22 0 1 -2 -33 ^ ^ ^ pivot free
huh...please use WebTEX for modellin equation..I thought it's just a single line EQN.
i figured it out, thanks
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