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f(x)=-3(x-2)^2-1 and g(x)=2x-3/x+5 A. f(g(2)) B. G(f(2))
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\[f(\frac{ 2x-3 }{ x+5 })\] it says f(g(2)) this means for the equation of g, the x values for it is 2 plug in 2 before you compose with the function of f.
after your done substituting that, you'll have f(and some number)
did i make it clear?
the thing that is throwing me of is the f(g(2)) thing
yeah, f(g(2)) is f of g of 2 g of 2 means that you plug in 2 in the function of g \[f(\frac{ 2(2)-3 }{ 2+5 })\]
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we are not composing f to g yet, we are composing g and 2 right now
so do the second question or part of the question(b) then go back to A
we are still solving for A, don't worry about the other problems, we are not there yet
okay
brb gotta switch computers lol
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