can someone help me
@Mrs.Mckinney With what?
how to solve 1/3s-8=t for s
\[\frac{ 1 }{ 3 }s - 8 = t\] for s
Alright you don't want a fraction when you want to solve for a variable, so you multiply the equation with 3. s - 24 = 3t Now you add 24 to the other side of the equation. s = 3t + 24
u lost me on the second one
2nd one?
s = 3t + 24?
Okay, you have \[(1/3)s-8=t\] You can add 8 to the right side, then multiply both sides by 3 to get \[s=3t+24\]
Basically what I just did lol
im talking about when u sent me, Alright you don't want a fraction when you want to solve for a variable, so you multiply the equation with 3. s - 24 = 3t Now you add 24 to the other side of the equation. s = 3t + 24 u lost me because i dont understand where u got s=3t+24 beacuas ethe problem was 1/3s-8=t for s so can u explain to me how u end up with s=3t+24
how did yall get s=3t+24
Ok? Well you multiply it all by 3, and 3 * 1/3 is canceling each other so it's 1 and 1 times anything is itself. -8 * 3 = -24. t * 3 = 3t (Three t's) Now you add the 24 so s can be by itself, because you want it alone to solve FOR S.
can u redo that please i dont understand it
Ahhh... (1/3)s * 3 = s -8 * 3 = -24 t * 3 = 3t When multiplying the equation by something, you take the number/variable and see if it's NEGATIVE or POSITIVE, which is why it's -8 * 3 = -24 instead of 8 * 3 = 24
When you add 24 to the other side, since it's negative and you only want to solve for s, it erases the -24 from the left side, and puts it on the right side.
no the 8 isn't negative the problem is set up like this 1/3s minus 8=t for s
Um, yes it is. Please listen to me. Take the equation apart, and you get 1/3s -8 = t
why are u taking it apart???
The minus sign isn't going to go in front of 1/3s- or else that would be I don't know, comprehensible.
TO SEE THAT THE 8 IS NEGATIVE
uncomprehensible**
my teacher dont do it that way
thats why im confused
Maybe you should listen to your teacher a bit more... and actually try to learn
Hi Mrs. First, do you understand why they multiplied each term by 3? That is to get rid of the fraction
@anisanox1 - that was very rude. Let me see if I can help her.
She's confused about the number 8 part
ok, I will help her.
I'm frustrated at how she can't understand I'm sorry if I seem that way.
Teen hormones and the such
That was very disrepectful and rude and u hurted my feelings....
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