Question

Can Anyone Help me please???

Answer 1

Can you help me @midhun.madhu1987 ?

Answer 2

Yes ... i'll try...

Answer 3

Haha ok o here is the question: Graph the function and label Zeros, Intersections, Vertices,and Asymptotes as appropriate. Function is f(x)=x+2/x-3

Answer 4

vertical asym where you have the function undefined
so x=3 is your vertical asymptote
zeros you solve x+2/x-3=0
bottom doesn't count since it cannot equal zero (we will have undefined)
so x+2=0 meaning x=-2
in another sense (-2,0) is your x-int
for y-int just plug in x=0
so 0+2/0-3=-2/3
(0,-2/3) y-int

Answer 5

y=1 would be the horizontal asym
since degree of num and denominator are equal (1,1)
we take their coefficients. in this case 1/1=1

Answer 6

vertices don't know what that is?

Answer 7

i think you are pretty much good to draw this rational function
you need some more point on the graph that's all

Answer 8

Oh Ok Well thanks for all of the help!

Answer 9

don't what vertices meant here! any idea? i could know what it is but
i haven't encountered the name before

Answer 10

and you are welcome^_^

Answer 11

i know what vertex is for parabolas o_O lol

Answer 12

@xapproachesinfinity you also know that vertices is the plural of vertex right?

Answer 13

that i know^_^, but no idea what they are asking here?

Answer 14

@triciaal any idea? lol

Answer 15

@xapproachesinfinity I think you did an excellent job!!
The only think not shown is the graph with all the points properly labeled. you have all the information for @sabercat9 to do that accurately..

Answer 16

well he/she needs to finish the work by his/her self^_^
i was hoping that i figure out what they want for vertices since i haven't done this for some time.