The surface area of this pyramid is one hundred eighty-nine square centimeters. The area of the square base is forty-nine square centimeters. What is the area of one triangular face of the lateral surface? Show the steps of your solution and explain your work. a square pyramid
A square pyramid is formed by a square base and four triangular faces surface area of pyramid = area of square + 4(area of triangle) 189 = 49 + 4(area of triangle) area of triangle = (189 - 49) /4 = 140/4 = ???
Thank you! :)
No problem. :)
@LXelle where did you get 140 Can you explain the steps to me?
189-49 i got 140
Do you think you may have made some (TYPO's) in your work above? Because it is not making sense... @LXelle
surface area of pyramid = area of square + 4(area of triangle) 189 = 49 + 4(area of triangle) area of triangle = (189 - 49) /4 = 140/4 = ??? makes more sense now?
Kind of... Thanks, I will try to put the pieces together...
Which part you arent clear of?
Isnt 189-49/4 176
So where did you get 140 from?
Remember your BODMAS.
In this case i put bracket for (189-49) THERES A BRACKET. MEANS YOU GOTTA WORK OUT THE BRACKET FIRST.
Oh...
So now when you do the brackets first why do you have to divide by 4 isn't that gonna give you a different answer?
Noooo. I did the braacketed one first, I didnt divide the 4 to get 140. Only (189-49)= 140. Dont get confused.
thats why you see i did \[\frac{ (189-49) }{ 40 }\]
Oh...
So in the end the answer should be 35?
yes
My workings is just a guide for you. Try to work out your own workings. Youll understand better.
Okay thanks I got it now. :)
Okay. Glad that you got it! :)
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