FOR A MEDAL Suppose the population of a town is 8,600 and is growing 1% each year. a. Write an equation to model the population growth. b. Predict the population after 12 years.
Why not explore a little? What would be the population after one year, given 1% growth?
8686
How did you get that? What is the population after two years?
1% each year means that the common ratio is 1.01
this is an exponential function which I like to refer to as a geometric sequence.
8600x.01 so 8772?
no, the function in your case should look like \(\Huge\color{black}{ y= \color{red}{(constant)}^\color{green}{x}}\)
Where, y is the number of people (overall), after years x.
oh ok i got it man thanks
Tell me what YOUR function is, please.
y=8600X1.01^x
y=(8600)^1.01 is correct. This is for the population. The population growth, should be that minus 8600 (not to include the initial pop.)
Try not to use "X" or "x" to mean multiplication. Very confusing. \(Population(t) = 8600(1.01)^{t}\) I do wish you had found it yourself. Oh, well.
YEah, you can put the multiplication symbol just using your keyboard without copy pasting. If you can how, then reply....
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