how to find out the area of a 4 1/3 base and 3 2/5 height parallelogram
If the height is the vertical height the area is found by multiplying the base by the height: \[\large Area=\frac{13}{3}\times\frac{17}{5}=(you\ can\ calculate)\ sq.\ units\]
Area A of a parallelogram = base x height. \(A = \Large 4\frac 13 \times 3 \frac 25 = \frac{13}{3} \times \frac{17}{5} = \frac{13\times 17}{3 \times 5} = \frac{?}{?}\)
uhm so 13 x 17 and 3 x 5 equals area 14.73????
The area is 14.73 square units, to two decimal places.
thank you :D i cant believe how simple it was but i didnt get it
You're welcome :) note: If the slant height is given instead of the vertical height, an internal angle must be given. Then it necessary to use simple trigonometry to find the vertical height.
Since the original dimensions were given as a mixed number I would probably leave the answer in mixed number too instead of decimals: \(\Large \frac{13\times 17}{3 \times 5} = \frac{221}{15} = 14\frac{11}{15}\)
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