Question

systems of equations with 3 variables

x+y+z=6
2x+y+2z=14
3x+3y+z

Answer 1

so far, i have multiplied the first equation by -2 and got -2x-2y-2z=-12, then i added it with the second equation and got y=-2. i dont know what to from there...

Answer 2

@aum

Answer 3

Multiply the first equation by -3 and add it to the third equation to find z.

Looks like the RHS of third equation is missing though.

Answer 4

the third equation is 3x+3y+z=8

Answer 5

i got 5 for z

Answer 6

Correct. Put y = -2 and z = 5 in first equation and find x.

Answer 7

3,-2,5?

Answer 8

Correct, but you should specify which variable has which value.
x = 3, y = -2, z = 5

Answer 9

ok, thanks. I have one more. can you check it when i finish?