Question

State the transformations, the domain and range, then graph the following

Answer 1

@Hero pleeeease help me!! :))))

Answer 2

@zepdrix pleasssse help me!!! :D

Answer 3

@aum plleaaasse help me :))))))

Answer 4

@Abhisar

Answer 5

@radar

Answer 6

@satellite73

Answer 7

What does \[y=\sqrt{x}\] look like?

Answer 8

oh yes, ik that. but i am confused how to graph it

Answer 9

@precal

Answer 10

are you doing number 2?

Answer 11

yes #2
idk how to get the coordinates
like do you see my work

Answer 12

kind of
ok your parent function is the square root function

Answer 13

\[y=\sqrt{x-2}+1\]

Answer 14

x y
0 0
1 1
4 2
9 3

Answer 15

idk how to do the square root function but i am familiar with the absolute value function

Answer 16

are you doing number 2? I am confused...which problem do you want me to help you with?

Answer 17

ok I am going to assume you need help with 2 then I really have to go.
+1 is the number outside of the square root, because it is positive, the function moves up 1 unit

Answer 18

yes, i got that but you see this
x y
0 0
1 1
4 2
9 3

^^ is that even right ???

Answer 19

oh yes sorry #2 sorry if i confused you

Answer 20

x-2 , remember that -2 is with x and it is under the square root sign. It moves in the opposite direction and therefore it moves 2 units to the right. I thought you needed help with transformations.

Answer 21

yes, i got that too. but then what do i do :)

Answer 22

the domain is all of the valid x values an range is all of the valid y values

Answer 23

are these the coordinates
x y
0 0
1 1
4 2
9 3

Answer 24

no because you are not using (0,0)

Answer 25

but can u ? :)

Answer 26

like i mean is it possible to plot 0,0

Answer 27

not for number 2