Question

Find the radius of the second orbit of hydrogen atom and calculate the energy when electron comes from second orbit to first orbit

Answer 1

Hello @kumarvibhutibhushan !

Answer 2

\(\huge \color{red}{\bigstar}\LARGE \color{blue}{\bigstar}\huge \color{green}{\bigstar}\LARGE \color{yellow}{\bigstar}\huge \color{orange}{\bigstar}\LARGE \color{red}{\bigstar}\huge \color{blue}{\bigstar}\LARGE\color{green}{\bigstar}\huge \color{yellow}{\bigstar}\LARGE \color{orange}{\bigstar}\huge \color{red}{\bigstar}\LARGE\color{blue}{\bigstar}\huge \color{green}{\bigstar}\LARGE\color{yellow}{\bigstar}\huge \color{red}{\bigstar}\LARGE \color{blue}{\bigstar}\huge \color{green}{\bigstar}\huge \color{yellow}{\bigstar}\LARGE \color{orange}{\bigstar}\\\color{white}{.}\\\Huge \rlap{\color{blue}{\mathfrak{~~~~Welcome~to~OpenStudy!~\ddot\smile}}}{\;\color{aqua}{\mathfrak{~~~~Welcome~to~OpenStudy!~\ddot\smile}}}\\\color{white}{.}\\\\\huge \color{red}{\bigstar}\LARGE \color{blue}{\bigstar}\huge \color{green}{\bigstar}\LARGE \color{yellow}{\bigstar}\huge \color{orange}{\bigstar}\LARGE \color{red}{\bigstar}\huge \color{blue}{\bigstar}\LARGE\color{green}{\bigstar}\huge \color{yellow}{\bigstar}\LARGE \color{orange}{\bigstar}\huge \color{red}{\bigstar}\LARGE\color{blue}{\bigstar}\huge \color{green}{\bigstar}\LARGE\color{yellow}{\bigstar}\huge \color{red}{\bigstar}\LARGE \color{blue}{\bigstar}\huge \color{green}{\bigstar}\huge \color{yellow}{\bigstar}\LARGE \color{orange}{\bigstar}\)

Answer 3

\(\huge \sf Radius =\frac{0.529\times n^2}{Z}\\ for~2nd~orbit~of~hydrogen~radius=0.529\times(2)^2=2.116~angstrom\)

Answer 4

Similarly,
\(\sf \huge Energy= \frac{-13.6\times Z^2}{n^2}eV\)
Energy of electron in second orbit will be -3.4 eV and that in first orbit will be -13.6eV. So during the given transition 10.eV of energy will be radiated.