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Quadratic formula: 4x^2 + 9 = 12x How do I solve this equation, if there is no "c" -b sqroot b^2-4ac / 2a
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\[4x^2 + 9 = 12x \\ 4x^2-12x+9=0\]
quadratic formula is for the form \[ax^2+bx+c=0\] only
So can you elaborate how exactly you did that and why?
Oh wait so you change it into that equation/form
the "why" is a good question, which i hope i answered with the second post
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the "how" is starting with \[4x^2 + 9 = 12x\] i subtracted \(12x\) from both sides, to put it in the necessary form
I got a -37.5 Which I'm thinking is wrong?
+4 -28 ?
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