Question

Can someone help me out with this problem please?

Evaluate the following expression using the values given:

Find 3x2 - y3 - y3 - z if x = 3, y = -2, and z = -5.

Answer 1

I take there are exponents?
Such as:
\[3x^2 - y^3 - y^3\]

Answer 2

Yes thats correct.

Answer 3

put the values of x y and z here

Answer 4

You are given the variables so plus them into the original equation.
\(x = 3, y = -2, z = -5 \implies 3(3)^2 - (-2)^3 - (-2)^3 - (-5)\)

Answer 5

Do you know how to evaluate from here?:
\[3(3)^2 - (-2)^3 - (-2)^3 - (-5)\]

@Originality

Answer 6

Sadly, I don't. :/

Answer 7

Okay, well do you understand everything I showed you before?

Answer 8

\(3(3)^3-(-2)^3-(-2)^3-(-5)\)
now what should you do
as \((3)^3\) means multiply 3 to three times like 3*3*3 as it has powers 3=27

similarly,
\((-2)^2\) has power 2 so multiply -2 two times like -2*-2=4

Answer 9

Yes, @ziqbal103 is correct, I assume he is taking lead now so I'll step back. :-)

Answer 10

\oh bove is not 3^2 but 3^3 so it would be -2*-2*-2=-8

Answer 11

and same way you take the next \(-(2)^3\)=-2*-2*-2=-8
and now it would be

\(3(27)-(-8)-(-8)-(-5)\)
keepit in your mind that always when two negative signs multiplied then it change into positive as done below
\(81+8+8+5=102\)

Answer 12

Is this for FLVS by any chance?