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OpenStudy (anonymous):
how can we find the value of \(\dfrac{1}{-tan135 degree}\)
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OpenStudy (anonymous):
@ganeshie8 @mathmath333 @surd @ash2326
OpenStudy (anonymous):
@paki @hartnn
OpenStudy (asnaseer):
what do you know about \(\tan(180-\theta)\) in terms of \(\tan(\theta)\)?
OpenStudy (anonymous):
welcome here after a long time here @asnaseer
OpenStudy (anonymous):
1/-tan135 =?just \(-tan135~dgre\)
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OpenStudy (asnaseer):
@ziqbal103 - please answer the question I asked above - its answer will guide you to how to calculate \(\frac{1}{-\tan(135^0)}\)
OpenStudy (anonymous):
yes its answer i want to ask ...as i know the values of 1/tan 2pi ...1/tan 60 degree but don't know its value
OpenStudy (asnaseer):
My question was:
What is \(\tan(180-\theta)=\)
in terms of \(\tan(\theta)\)?
OpenStudy (asnaseer):
for any \(\theta\)
OpenStudy (anonymous):
for theta =-tan135
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OpenStudy (asnaseer):
no.
e.g.:\[\sin(180-\theta)=\sin(\theta)\]\[\cos(180-\theta)=-\cos(\theta)\]so:\[\tan(180-\theta)=?\]
OpenStudy (asnaseer):
have you heard of the CAST acronym related to trigonometry?
OpenStudy (anonymous):
what is CAST? sorry i don;t know
OpenStudy (asnaseer):
|dw:1409397909868:dw|
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