Can someone help me with this?! :// Sum of the equation(tan(2x+pi/4)=sqrt3 ) solutions for interval x€[0,pi) is?
Where is the tangent equal to sqrt(3)?
i know that the arctan of sqrt is pi/3
and that tan of pi/4 is 1 but idk what to do with it..
I think 2x + pi/4 = 60
how?
(tan(2x+pi/4)=sqrt3 ) arctan of sqrt 3
No, 2x + pi/4 = pi/3 + kpi where k is any integer. There are LOTS of solutions.
but i need to write the sum of the solutions in the interval above..
You must first find them all. 2x = pi/12 + kpi x = pi/24 + kpi/2 How many values of k put the corresponding value of x in the desired interval?
0,pi/2,pi/3,pi/4? °_°
also i never understood these : 2x = pi/12 + kpi x = pi/24 + kpi/2 are those always the same and how do i know which ones to use and when?
|dw:1409426495288:dw| @tkhunny is this corrrect
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