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OpenStudy (dawnr):
Can someone help me with this?! ://
Sum of the equation(tan(2x+pi/4)=sqrt3 ) solutions for interval x€[0,pi) is?
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OpenStudy (tkhunny):
Where is the tangent equal to sqrt(3)?
OpenStudy (dawnr):
i know that the arctan of sqrt is pi/3
OpenStudy (dawnr):
and that tan of pi/4 is 1
but idk what to do with it..
OpenStudy (triciaal):
I think 2x + pi/4 = 60
OpenStudy (dawnr):
how?
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OpenStudy (triciaal):
(tan(2x+pi/4)=sqrt3 )
arctan of sqrt 3
OpenStudy (tkhunny):
No, 2x + pi/4 = pi/3 + kpi where k is any integer. There are LOTS of solutions.
OpenStudy (dawnr):
but i need to write the sum of the solutions in the interval above..
OpenStudy (tkhunny):
You must first find them all.
2x = pi/12 + kpi
x = pi/24 + kpi/2
How many values of k put the corresponding value of x in the desired interval?
OpenStudy (dawnr):
0,pi/2,pi/3,pi/4? °_°
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OpenStudy (dawnr):
also i never understood these : 2x = pi/12 + kpi
x = pi/24 + kpi/2
are those always the same and how do i know which ones to use and when?
OpenStudy (triciaal):
|dw:1409426495288:dw|
@tkhunny is this corrrect
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