Question

Simplify and write in terms of sine.
tanβ/cosβ

Answer 1

sinB/cosB = tanB
so tanBcosB=sinB
so tanB/cosB=?

Answer 2

sinB? @purplerainbowcherry

Answer 3

\[\dfrac{\tan\beta}{\cos\beta} = \dfrac{\frac{\sin\beta}{\cos\beta}}{\cos\beta} = \dfrac{\sin\beta}{\cos^2\beta}\]

Try to replace \(\cos^2\beta\) into expression only in terms of sine. HINT: \(\sin^2\beta+\cos^2\beta=1\)

Answer 4

I got \[\frac{ \sin \beta }{ 1- \sin^2 \beta }\] @micahwood50

Answer 5

@purplerainbowcherry ^

Answer 6

yup, it's right :)

Answer 7

Thank you