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Mathematics 20 Online
OpenStudy (henrietepurina):

Please Help Algebra 1 question... Medal + Fan :)

OpenStudy (henrietepurina):

The table represents data collected on the time spent studying (in minutes) and the resulting test grade. Time Spent Studying (min) 52 37 31 9 26 40 22 10 45 34 19 60 Grade on Test 95 84 72 58 77 86 72 43 90 81 62 98

OpenStudy (henrietepurina):

Part 1: Create a scatter plot with the predicted line of best fit drawn on it. Determine the type of correlation (if any), and predict the model that will be used. Part 2: Find the line of best fit for the data either by hand or using technology. Explain your method. Find the predicted score for each time listed in the table. Part 3: Find the residuals, and decide if your model is a good fit. Explain your method. (If your model is not a good fit, complete Part 2 again with a different set of points or choose a different model.)

OpenStudy (anonymous):

so take it one step at a time

OpenStudy (anonymous):

do u know how to make a scatter plot?

OpenStudy (abb0t):

I'm pretty sure that your computer has \(Excel\) which you can use to create a scatter plot!. Then, right-click on one of the points, then click "add trendline" which is like best-fit line.

OpenStudy (henrietepurina):

No, I have a mac... also I have done a few things in the first part.

OpenStudy (henrietepurina):

Positive correlation, and a linear model with a positive rate of progress will be used.

OpenStudy (anonymous):

a scatter plot is basic just make a graph like the one in a screenshot and put grade on the bottom and time spent studying on the left, then fill in points

OpenStudy (henrietepurina):

what do you mean fill in points?

OpenStudy (abb0t):

Mac should come with Excel when you bought it. You can get the student version of office that comes with Excel, PowerPoint and Word.

OpenStudy (henrietepurina):

oooh... would numbers do?

OpenStudy (henrietepurina):

numbers (something like excel)

OpenStudy (henrietepurina):

look it up :) I dont have excel :(

OpenStudy (anonymous):

for example. the first grade on the test is a 95, you would go to the 95, then go up to 52 (which is the time spent studying, then put a dot there, you would do that with each set of numbers

OpenStudy (henrietepurina):

Could you show me? :)

OpenStudy (henrietepurina):

@alex1248191

OpenStudy (anonymous):

yep!

OpenStudy (anonymous):

|dw:1409597900124:dw|

OpenStudy (anonymous):

like that but your numbers can be whatever u want as long as they include the given

OpenStudy (henrietepurina):

thanks, do you think you could help add points to the graph. would the first point be at (52,95) ???

OpenStudy (anonymous):

yes, except you would look at 95 first then go to 52

OpenStudy (henrietepurina):

ok thanks... ill graph it...

OpenStudy (henrietepurina):

doesnt this already have points?

OpenStudy (henrietepurina):

so @alex1248191

OpenStudy (anonymous):

sorry i had to leave my computer for a sec, and yes it does,

OpenStudy (henrietepurina):

ok so next step... Determine the type of correlation (if any)... I said - Positive correlation, and a linear model with a positive rate of progress will be used.

OpenStudy (anonymous):

Yes that is correct!

OpenStudy (henrietepurina):

ALRIGHT! :) Time for Part 2 :)

OpenStudy (henrietepurina):

Find the line of best fit for the data either by hand or using technology.

OpenStudy (henrietepurina):

Sorry about that before...

OpenStudy (henrietepurina):

what does it mean to find the line of best fit for the data either by hand or using technology?

OpenStudy (anonymous):

it mean to find the line that best fits for all of the data you have entered

OpenStudy (henrietepurina):

Dont I already have one? No?

OpenStudy (anonymous):

Yes you do, so that one is the best fitting one

OpenStudy (henrietepurina):

Ok, so now I have to explain my method...

OpenStudy (anonymous):

ok, so explain to me the methid

OpenStudy (henrietepurina):

IDK... I just planted the points and I forgot what next...

OpenStudy (anonymous):

you used the graphing method sence you graphed the points

OpenStudy (anonymous):

didnt mean to send that last message again

OpenStudy (henrietepurina):

yeah I guess so

OpenStudy (henrietepurina):

@alex1248191

OpenStudy (anonymous):

so you got it now!

OpenStudy (henrietepurina):

kinda... explain it to me

OpenStudy (anonymous):

Ok, so the method you used is the graphing points methond,, you looked at the graph and filled in the points at the appropiate spot, you then looked at the date and decided that the line draw best fits that graph

OpenStudy (henrietepurina):

yeah... so could I write this? : I looked at the graph and filled in the points at the appropiate spot, you then looked at the date and decided that the line draw best fits that graph.

OpenStudy (henrietepurina):

@alex1248191

OpenStudy (anonymous):

yep!

OpenStudy (henrietepurina):

I have written this so far for part 2... My best line of fit is in the graph above and would have a slope of m=15x+45.

OpenStudy (anonymous):

that good

OpenStudy (henrietepurina):

The graph above is the one we have

OpenStudy (henrietepurina):

Can you now help me to find the predicted score for each time listed in the table.

OpenStudy (henrietepurina):

@alex1248191

OpenStudy (anonymous):

im not sure how to do that, i'll get back with you asap, imma figure it out

OpenStudy (henrietepurina):

ok

OpenStudy (henrietepurina):

you got anything?

OpenStudy (henrietepurina):

have you got anything?

OpenStudy (anonymous):

naw not yet

OpenStudy (henrietepurina):

ok tell me when you get something

OpenStudy (anonymous):

ight

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