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5/2y=(y+5) how do u solve it??
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first step multiple both sides by 2y
\[\frac{ 5 }{ 2y }=(y+5)\] \[5=2y(y+5)\] \[5=2y ^{2}+10y\] \[0=2y^{2}+10y-5\] now factor
how do u factor that?? help :( thanks!
This wont factor so you need to use the quadratic formula ok
A=2,B=10,C=-5 \[y=\frac{ -b \sqrt{b^{2}-4ac} }{ 2a }\]
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it would be 150/2 or -130/2 right?
http://www.algebra.com/algebra/homework/Inverses/Inverses.faq.question.210989.html here ya go.
so whats the answer then?
its at the bottom i believe. i don't have a calculator right now or id solve it for you.
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