HELP PLEASE
The height of a tower is three times the height of a certain building. If the tower is 50 m taller than the building, how tall is the tower?
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OpenStudy (kkutie7):
t=tower height b=building height
t=3*b
t=50m+b a way to think of it.
OpenStudy (anonymous):
OKAYYY so what do i do?
OpenStudy (kkutie7):
b=t/3
t=50+t/3
t-50=t/3
3t-150=t
-150=t-3t
-150=-2t
150=2t
75m=t
I think this is right. you might want to check it out.
OpenStudy (anonymous):
this is really confusing
OpenStudy (kkutie7):
ok let me break it down for you
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OpenStudy (anonymous):
alright
OpenStudy (kkutie7):
t=tower height
b=building height
t=3*b because The height of a tower is three times the height of a certain building
t=50m+b because tower is 50 m taller than the building
are you with me so far?
OpenStudy (anonymous):
yep so far so good!
OpenStudy (kkutie7):
alright good =)
what I did was take one of the equations ad solve for b.
\[t=3*b\]
\[\frac{t}{3}=b\]
OpenStudy (anonymous):
aye wait!
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OpenStudy (kkutie7):
yes?
OpenStudy (anonymous):
wouldnt it be 3b=t
OpenStudy (kkutie7):
no because we are solving for b not t
OpenStudy (anonymous):
oh okay
OpenStudy (anonymous):
but i dont understand how you got t over 3?
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OpenStudy (kkutie7):
ok so t=3xb right? so in order to get b on one side of the equal sign by itself you need to divide both sides by 3 so \[\frac{t}{3}=\frac{3b}{3}\]