what is the factored form of the expression 6x^2+13x+ 5

Question

anonymous · Answer

Yes

anonymous · Answer

Thank you

solomonzelman · Answer

yes, and the  b²-4(a)(c)    (the piece that is in the square root, in a quadratic formula) has to be a perfect square.

anonymous · Answer

yes it can be (3x-1) and (2x+5)

aum · Answer

6x^2+13x+ 5 = 
6x^2 + 10x + 3x + 5 = 
2x(3x + 5) + 1(3x + 5) = 
(2x + 1)(3x + 5)

aum · Answer

The above is the AC method of factoring.
6x^2+13x+ 5
In AC method you find the product of the coefficients A and C
A = 6, C = 5, A*C = 30
split the middle coefficient 13 into two parts so that the sum is 13 and the product is 30.
10 + 3 = 13
10 x 3 = 30
Therefore, 6x^2 + 13x + 5 = 6x^2 + 10x + 3x + 5 and then you factor as shown in previous reply.