8Ix+3/4I <2
A. x<-1 5/6 or 5/6
B .x= -1 or x= 41/3
C. x= -1 5/6 or 4 1/3
D. x= -1 5/6 or X= -1
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OpenStudy (xapproachesinfinity):
okay let's play this game hehe
the game says first divide both side of the inequality by 8
OpenStudy (anonymous):
is 1.5 the same as 1/2
OpenStudy (xapproachesinfinity):
Now next step is matching this with another rule of the game
with is if |x|<a then -a<x<a this is called conjunction
OpenStudy (xapproachesinfinity):
Nope!
OpenStudy (anonymous):
8Ix+3/4I <2
Ix+3/4I <1/4
So x+3/4<1/4
and x+3/4 >-1/4
So x<-0.5 and x>-1
x (-1, -0.5)
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OpenStudy (xapproachesinfinity):
1.5 is 3/2
1/2=0.5 surely 3/2>1/2
OpenStudy (xapproachesinfinity):
@WilliamZhang pls do not give complete answers!
OpenStudy (anonymous):
okay so where are we at in the equation
OpenStudy (xapproachesinfinity):
so can you apply the rules of this game to this?
OpenStudy (anonymous):
no...
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OpenStudy (xapproachesinfinity):
we said first divide by 8 both sides
then look at what case do we have
OpenStudy (anonymous):
4
OpenStudy (xapproachesinfinity):
if |x|<a conjunction then -a<x<a
OpenStudy (xapproachesinfinity):
a must be positive though to apply this!
just a warning
OpenStudy (anonymous):
so then it would be C
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OpenStudy (xapproachesinfinity):
man! do the word and see what you get
OpenStudy (xapproachesinfinity):
work*
OpenStudy (xapproachesinfinity):
Do you want to play the game or not?
if not! no answer for you
OpenStudy (xapproachesinfinity):
think of this as a game will ya!
OpenStudy (anonymous):
well im trying to figure out but I don't think the game is working
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OpenStudy (xapproachesinfinity):
well the game is good to me!
we started at \(8|x+\frac{3}{4}|<2\)
dividig by 8
\( \large\frac{8}{8}|x+\frac{3}{4}|<\frac{2}{8}\)
8/8 is just 1
so
\( |x+\frac{3}{4}|<\frac{1}{4}\)
2/8 is 1/4 the game said so haha
no you have conjuction
OpenStudy (anonymous):
Simplify the inequality ,
Then,if |A|<B
then -B<A<B.
Do the simple algebra. Thats it.
OpenStudy (xapproachesinfinity):
now* not "n" sorry
OpenStudy (xapproachesinfinity):
well! how about you continue this game?
OpenStudy (anonymous):
k
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OpenStudy (xapproachesinfinity):
so according to our game rule what should we do next?
OpenStudy (anonymous):
add
OpenStudy (xapproachesinfinity):
add what
i will repost the games rule
if |x|<a, a is positive
then -a<x<a
OpenStudy (xapproachesinfinity):
I keep saying this many times you pay attention to it^_^
OpenStudy (xapproachesinfinity):
a is our case is 1/4
x is our case is x+3/4
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OpenStudy (xapproachesinfinity):
can you see it now?
OpenStudy (anonymous):
so divide the 3/4 to 1/4
OpenStudy (xapproachesinfinity):
in our case*
sorry for bad miss spelling
OpenStudy (xapproachesinfinity):
No!
look
|x|<a, so is becomes -a<x<a
OpenStudy (xapproachesinfinity):
instead of a put 1/4
instead of x put x+3/4
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OpenStudy (anonymous):
so x+ 3/4 <1/4
OpenStudy (xapproachesinfinity):
but i want you to remember that a should be positive to do this
rule otherwise we would have done a different thing! just keep this in mind for future problems^_^
OpenStudy (xapproachesinfinity):
what about the other side of the inequality?
-a<x<a
look and see if you did the right thing?
OpenStudy (anonymous):
-1< x<-0.5 ,
A. x<-1 5/6 or 5/6
B .x= -1 or x= 41/3
C. x= -1 5/6 or 4 1/3
D. x= -1 5/6 or X= -1
so no above is correct.
OpenStudy (xapproachesinfinity):
@WilliamZhang pls no answers don't confuse our friend
we trying to learn this. we are not trying to just solve it?
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OpenStudy (xapproachesinfinity):
we teach me how i fish not give me the fish lol
if you give me the fish next time you are not around i cannot get the fish
OpenStudy (anonymous):
Sorry, I am just confused about the options.
OpenStudy (xapproachesinfinity):
we will see it through if there is anything but let's keep it simple for now
OpenStudy (anonymous):
@WilliamZhang A <-1 or X >-1/2
B -5/32<x<5/32
C -1 ,x, -1/2
D is <-5/32 or x> 5/32
OpenStudy (anonymous):
sorry I typed out something different
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OpenStudy (xapproachesinfinity):
i figured out that! So i was gonna ask you to relook at
but that was not important for now!
OpenStudy (xapproachesinfinity):
once we get the right thing you would look at the answer and you will say look
that is the what i got too in this game lol
OpenStudy (anonymous):
so its positive we know that
OpenStudy (xapproachesinfinity):
now pls go back to where we are
you said x+3/4<1/4
but i said that's not complete?
OpenStudy (anonymous):
so it would be B
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OpenStudy (anonymous):
8|A|<2
|A|<2/8
|A|<(2*1)/(2*4)
|A|<1/4
U get it?
Then,
if |A|<B
then -B<A<B. U have to remember this.
OpenStudy (xapproachesinfinity):
Again you said be! i don't really care whether is A or B or C or D
our main focus is to solve this.
OpenStudy (xapproachesinfinity):
and learn how to do it!
OpenStudy (anonymous):
1/4< x=3/4 <14
OpenStudy (xapproachesinfinity):
in fact i haven't looked at the solution yet haha.
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OpenStudy (anonymous):
so we would divde
OpenStudy (xapproachesinfinity):
that is incorrect! relook at it again?
OpenStudy (anonymous):
that's how I just learned it
OpenStudy (xapproachesinfinity):
i said -a<x<a
OpenStudy (anonymous):
-1/4 <3/4x <1/4
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OpenStudy (xapproachesinfinity):
that is okay! learning take time! don't be afraid! ashamed or anything! okay
just continue learning. no matter say i have to learn it
OpenStudy (xapproachesinfinity):
you have x+3/4 how did it become 3/4x?
OpenStudy (anonymous):
that's what I meant
OpenStudy (xapproachesinfinity):
the other parts are fine^_^
OpenStudy (xapproachesinfinity):
okay! be very precise! math is precise^_^
so -1/4<x+3/4<1/4
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OpenStudy (anonymous):
so divide -1/4and 3/4
OpenStudy (xapproachesinfinity):
now we want to separate x by it self
so we need to subtract 3/4
but we need to subtract it from all side
OpenStudy (anonymous):
so subtract 3/4 by 1/4
OpenStudy (xapproachesinfinity):
Not divide!
we don't have multiplication to divide
we have addition here so subtraction is needed
OpenStudy (xapproachesinfinity):
look at this -1/4-3/4<x+3/4-3/4<1/4-3/4
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