Question

find q if p varies directly as the square of q and k=8 and p=64

Answer 1

\[p=k*\sqrt{q}\]

Answer 2

thats it?

Answer 3

\[64=8*\sqrt{q}\]
\[64/8=\sqrt{q}\]
\[(8)^2=q\]

Answer 4

@Abmon98 what happened to the square root?

Answer 5

When we move the square to the other side of the equation the fraction 1/2 is inverted to 2

Answer 6

@Abmon98 im sorry i dont get it :(

Answer 7

so you should learn that y^1/2 means the square root of y
we get rid of that square root , by squaring both sides
\[(\sqrt{q})^2=8^2\]
\[(q ^{1/2})^2=q\]
2 gets cancelled by the other 2

Answer 8

so the answer is 64 ? @Abmon98