Graph the following equation reflecting a basic function. f(x)= sqrt -x
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OpenStudy (darkbluechocobo):
OpenStudy (darkbluechocobo):
@geerky42
geerky42 (geerky42):
\(\sqrt{-x}\)...
So basically what happened is that every negative inputs will become positive, lead them to have outputs.
And positive inputs will be negative, hence no outputs.
geerky42 (geerky42):
Sound like function "flips" across y-axis
OpenStudy (darkbluechocobo):
so if it is positive it would be the first one right?
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OpenStudy (darkbluechocobo):
since sqrt -x would look like
geerky42 (geerky42):
Yea, you got that right!
OpenStudy (darkbluechocobo):
Yay :3 thank you for confirming with me haha :3
geerky42 (geerky42):
welcome :)
OpenStudy (darkbluechocobo):
wait to be sure this one is the correct one
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OpenStudy (darkbluechocobo):
OpenStudy (xapproachesinfinity):
the first one is \(-\sqrt{-x}\)
OpenStudy (xapproachesinfinity):
it is the image of \(\sqrt{x}\) symmetry to the origin
OpenStudy (xapproachesinfinity):
Oh i see you started with \(\sqrt{-x}\) i thought you started from parent function
OpenStudy (darkbluechocobo):
aha yah he said that i would be positive so i just flipped around what -sqrtx would be
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