Question

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Answer 1

Yes ! you can use IVT

Answer 2

you got it @QueenBee232

Answer 3

did u check each options and none of them gave u opposite signs ?

Answer 4

if u can, please take a screenshot of original problem and attach

Answer 5

thats the reason i wanted a screenshot, the options make no sense for the given function

Answer 6

the options are more related to inverse sine function, attach a screenshot so that we can avoid this discussion/confusion

Answer 7

okay ask ur teacher to correct the options, also ask her to specify whether the x is in degrees or radians

Answer 8

this question has issues, leave it and move on to other questions

Answer 9

nope, the function needs to be continuous in the interval [a, b] including the boundary values

Answer 10

Notice that the function discontinuous at pi/2,
so you cannot apply IVT in terval [-pi/3, pi/2]

Answer 11

hello?