Determin the value(s) of angle x, 0
Ah I found you! =)
ok so lets start with a) \[Sin(x)=-(\frac{1}{\sqrt{2}})\] Sin on a graph can be thought of a the y coordinate when is y negative?
|dw:1409804367037:dw| we can see that in quadrant 3 and 4 are where y is negative.
note: above will come in hand later but not too much of a deal right now you wanna think of a triangle. there are two different ones but for this one we will always use this triangle. |dw:1409804601975:dw|
sin= opposite over hypotenuse . so either 45 degrees will work.
its hard to say with b) because we don't have a sin cos or tan. but for \[\frac{\sqrt{3}}{2}\] you will need to use another triangle. this one. |dw:1409804888012:dw|
so Sin(60) will work or Cos(30)
here is a cheat sheet for when you get stuck. sin=y and cos=x http://etc.usf.edu/clipart/43200/43216/unit-circle8_43216_lg.gif
Thank you so much. :)
any time. I hope this makes sense
yes, its a bit confusing but when i copy it down it'll probably make more sense
ask any questions if you need to. memorize those two triangles because they will come in hand to do things quickly
Okay, Thanks again
I just remembered why I put the quadrant in there. The degree is going to bigger that 180. So 180 +45 for one of them and 360-45 for the other. Sorry about that.
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