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Mathematics 10 Online
OpenStudy (zahrakkhan):

Determin the value(s) of angle x, 0

OpenStudy (kkutie7):

Ah I found you! =)

OpenStudy (kkutie7):

ok so lets start with a) \[Sin(x)=-(\frac{1}{\sqrt{2}})\] Sin on a graph can be thought of a the y coordinate when is y negative?

OpenStudy (kkutie7):

|dw:1409804367037:dw| we can see that in quadrant 3 and 4 are where y is negative.

OpenStudy (kkutie7):

note: above will come in hand later but not too much of a deal right now you wanna think of a triangle. there are two different ones but for this one we will always use this triangle. |dw:1409804601975:dw|

OpenStudy (kkutie7):

sin= opposite over hypotenuse . so either 45 degrees will work.

OpenStudy (kkutie7):

its hard to say with b) because we don't have a sin cos or tan. but for \[\frac{\sqrt{3}}{2}\] you will need to use another triangle. this one. |dw:1409804888012:dw|

OpenStudy (kkutie7):

so Sin(60) will work or Cos(30)

OpenStudy (kkutie7):

here is a cheat sheet for when you get stuck. sin=y and cos=x http://etc.usf.edu/clipart/43200/43216/unit-circle8_43216_lg.gif

OpenStudy (zahrakkhan):

Thank you so much. :)

OpenStudy (kkutie7):

any time. I hope this makes sense

OpenStudy (zahrakkhan):

yes, its a bit confusing but when i copy it down it'll probably make more sense

OpenStudy (kkutie7):

ask any questions if you need to. memorize those two triangles because they will come in hand to do things quickly

OpenStudy (zahrakkhan):

Okay, Thanks again

OpenStudy (kkutie7):

I just remembered why I put the quadrant in there. The degree is going to bigger that 180. So 180 +45 for one of them and 360-45 for the other. Sorry about that.

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