Question

how do i find a simpler function that agrees to this function?

lim as x approaches 0 for e^2x-1/e^x-1

Answer 1

factor and cancel

Answer 2

\[\frac{x^2-1}{x-1}=x+1\]

Answer 3

how exactly did you factor?.

Answer 4

\(e^{2x} - 1 = (e^x)^2 - 1^2 = (e^x+1)(e^x-1)\)

Answer 5

oh ! okay, then x-1 cancels out and leaves you with x+1 ?

Answer 6

\(e^x-1\) cancels out leaving you with \(e^x+1\)

Answer 7

i confused you sorry
\[\frac{e^{2x}-1}{e^x-1}=\frac{(e^x-1)(e^x+1)}{e^x-1}=e^x+1\]

Answer 8

oh so then the limit would =1 right?

Answer 9

\[e^0+1=?\]

Answer 10

wait sorry 2

Answer 11

yup

Answer 12

thank you!