Vectors A=(2,1,-4), B=(-3,0,1). What is the angle (thetaAB) between A and B? Can someone guide me or explain me how to solve this?
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check out this page http://www.mathsisfun.com/algebra/vectors-dot-product.html the formula works for any type of vectors (in 2space, 3space, etc)
I did but I am still unsure how to do the problem above. I'm trying to figure it out.
what is the dot product of those two vectors?
to be honest I have 0 knowledge about vectors so I just started reading about it. I am not sure how to approach this one though.
your teacher never went over dot products at all?
Uhm well I just started physics on college and the professor started talking about it and I had never done that so I am completely lost on this subject.
did you look at the link I posted? Did that article make any sense at all?
it explains how to compute the dot product basically you multiply the corresponding components, then add the products up
yes. I can solve for some but I still don't understand how to approach this by looking at the website.
I can do A*B = AxBx + AyBy + AzBz
what dot product did you get
but I am not sure how to approach this one
do I have to do something like this? A*B= (AxBx+AyBy+AzBz)cos(theta)?
close
on the left side, you should have |A|*|B| the vertical bars tell us to find the length of each vector
actually wait hold on
the formula is actually AxBx+AyBy+AzBz = |A|*|B|*cos(theta)
I see |A|*|B|*cos(theta)
yeah that's it
oh oh
|A|*|B|*cos(theta) is equal to the dot product so the dot product and the angle between vectors are connected ideas
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