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Mathematics 12 Online
OpenStudy (anonymous):

Vectors A=(2,1,-4), B=(-3,0,1). What is the angle (thetaAB) between A and B? Can someone guide me or explain me how to solve this?

OpenStudy (anonymous):

|dw:1409957609618:dw|

jimthompson5910 (jim_thompson5910):

check out this page http://www.mathsisfun.com/algebra/vectors-dot-product.html the formula works for any type of vectors (in 2space, 3space, etc)

OpenStudy (anonymous):

I did but I am still unsure how to do the problem above. I'm trying to figure it out.

jimthompson5910 (jim_thompson5910):

what is the dot product of those two vectors?

OpenStudy (anonymous):

to be honest I have 0 knowledge about vectors so I just started reading about it. I am not sure how to approach this one though.

jimthompson5910 (jim_thompson5910):

your teacher never went over dot products at all?

OpenStudy (anonymous):

Uhm well I just started physics on college and the professor started talking about it and I had never done that so I am completely lost on this subject.

jimthompson5910 (jim_thompson5910):

did you look at the link I posted? Did that article make any sense at all?

jimthompson5910 (jim_thompson5910):

it explains how to compute the dot product basically you multiply the corresponding components, then add the products up

OpenStudy (anonymous):

yes. I can solve for some but I still don't understand how to approach this by looking at the website.

OpenStudy (anonymous):

I can do A*B = AxBx + AyBy + AzBz

jimthompson5910 (jim_thompson5910):

what dot product did you get

OpenStudy (anonymous):

but I am not sure how to approach this one

OpenStudy (anonymous):

do I have to do something like this? A*B= (AxBx+AyBy+AzBz)cos(theta)?

jimthompson5910 (jim_thompson5910):

close

jimthompson5910 (jim_thompson5910):

on the left side, you should have |A|*|B| the vertical bars tell us to find the length of each vector

jimthompson5910 (jim_thompson5910):

actually wait hold on

jimthompson5910 (jim_thompson5910):

the formula is actually AxBx+AyBy+AzBz = |A|*|B|*cos(theta)

OpenStudy (anonymous):

I see |A|*|B|*cos(theta)

jimthompson5910 (jim_thompson5910):

yeah that's it

OpenStudy (anonymous):

oh oh

jimthompson5910 (jim_thompson5910):

|A|*|B|*cos(theta) is equal to the dot product so the dot product and the angle between vectors are connected ideas

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